Question

find f(x) = (2x²-3x-2)
g(x) = x³-4x²+4x​

Answer 1

$1. \\ 0 = (2 {x}^{2} - 3x - 2) \\ 0 =( 2 {x}^{2} - 4x + x - 2) \\ 0 = 2x(x - 2) + 1(x - 2) \\ 0 = (x - 2)(2x + 1) \\ x = 2 \: or \: x = - \frac{1}{2}$

$2. \\ 0 = {x}^{3 } - 4 {x}^{2} + 4x \\ 0 = x( {x}^{2} - 4x + 4) \\ 0 = {x}^{2} - 4x + 4 \\ 0 = {x}^{2} - 2x - 2x + 4 \\ 0 = x(x + 2) - 2(x + 2) \\ 0 = (x + 2)(x - 2) \\ x = 2 \: or \: x = - 2$