Find f (x) + f (1- x) if f (x) = + √
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Answered by
0
Given ,
f(x)=
x+1
x
diff. w.r.t x
f
′
(x) =
2
x
(x+1
2
)
1−x
put x=1
f
′
(1) =
2
1
(1+1
2
)
1−1
f
′
(1) =0
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