Question

find factirs of y²-31y+240=0​

Answer 1

Step-by-step explanation:

=−±2−4√2

y=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}y=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2−31+240=0

y^{2}-31y+240=0y2−31y+240=0

=1

a={\color{#c92786}{1}}a=1

=−31

b={\color{#e8710a}{-31}}b=−31

=240

c={\color{#129eaf}{240}}c=240

=−(−31)±(−31)2−4⋅1⋅240√2⋅1

y=\frac{-({\color{#e8710a}{-31}}) \pm \sqrt{({\color{#e8710a}{-31}})^{2}-4 \cdot {\color{#c92786}{1}} \cdot {\color{#129eaf}{240}}}}{2 \cdot {\color{#c92786}{1}}}y=2⋅1−(−31)±(−31)2−4⋅1⋅240

2

Answer 2

y²-31y+240=0

y²-16y-15y+240=0

y(y-16)-15(y-16)=0

(y-15)(y-16)=0

y-15=0 or y-16=0

y=15 or y=016