Question

find factor of a cube minus b cube plus 1 plus 3ab​

Answer 1

Answer:

x^3+y^3+z^3–3.x.y.z =(x+y+z) (x^2+y^2+z^2-xy-yz-zx).

Question:-

=(a)^3 +(-b)^3 + (1)^3 -3.a.(-b).1

=[a+(-b,)+1] [(a)^2+((- b)^2+(1)^2-a.(- b)-(-b).1- 1.a]

=(a-b+1) (a^2+b^2+1+a.b+b-a) , Answer.

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