Question

find factor theorum ​

Answer 1

x - 2 = 0

x = 0 + 2 (negative to positive)

x = 2

$p(x) = ( {x}^{3 } - 8) \\ p(2) = ( {2}^{3} - 8) \\ = (2 \times 2 \times 2 - 8) \\ = 8 - 8 \\ 0$

yes (x - 2) is a factor of (x to the power 3 - 8)

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