Math, asked by pantnagarlucknow, 9 months ago

Find factorisation

x⁴+2x²+9​

Answers

Answered by silentlover45
7

Formula used:

a² - b² = (a + b)(a - b)

a² + b² = (a + b)² - 2ab

Solutions:

x⁴ + 2x² + 9

(x²)² + (3)² - 2.x².3 + 2x²

(x² + 3)² - 6x² + 2x²

(x² + 3)² - (2x)²

(x² + 2x + 3)(x² - 2x + 3).

silentlover45.❤️

Answered by pulakmath007
3

x⁴ + 2x² + 9 = (x² + 2x + 3)(x² - 2x + 3)

Given :

The expression x⁴ + 2x² + 9

To find :

To factorise the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

x⁴ + 2x² + 9

Step 2 of 2 :

Factorise the expression

\displaystyle \sf{ {x}^{4}    + 2 {x}^{2}  + 9}

\displaystyle \sf{ =  {x}^{4}    + 9 + 2 {x}^{2}  }

\displaystyle \sf{ =  {( {x}^{2} )}^{2}    +  {(3)}^{2} + 2. {x}^{2} .3 -   2. {x}^{2} .3+ 2 {x}^{2}  }

\displaystyle \sf{ =  {( {x}^{2} + 3 )}^{2}   -  6 {x}^{2}+ 2 {x}^{2}  }

\displaystyle \sf{ =  {( {x}^{2} + 3 )}^{2}   -  4 {x}^{2}}

\displaystyle \sf{ =  {( {x}^{2} + 3 )}^{2}   -   {(2x)}^{2}}

\displaystyle \sf{ = ( {x}^{2}  + 3 + 2x)( {x}^{2}  + 3  -  2x)}

\displaystyle \sf{ = ( {x}^{2}  + 2x + 3)( {x}^{2}   -  2x + 3)}

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