Question

find factors of 3y2-2y-1​

Answer 1

Step-by-step explanation:

3y^2-2y-1

=3y^2-(3-1)y-1

=3y^2-3y+y-1

=3y(y-1)+1(y-1)

=(y-1)(3y+1)

Answer 2

3y²-2y-1=0

»»»» solving by using the equation

(-b±√b²-4ac)/2a

(-(-2)±√2²-4×3×-1)/2×3

(2±√4+12)/6

(2±√16)/6

(2±4)/6

2+4/6 2-4/6

6/6 -2/6

=1 = -1/3

therefore, the factors are 1&-1/3