find factors or route of (2x2-3x-2)(2x2-3x)-63
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Answer:(2x+3) (x-3) (2x^2-3x+7)
Step-by-step explanation:
(2x2-3x-2)(2x2-3x)-63
Put 2x^2-3x= y, we get,
(y - 2) y -63
= y^2-2y-63
= y^2 -9y+7y-63= y(y-9)+7(y-9)
= (y-9)(y+7) and putting value of y,
= (2x^2-3x-9) (2x^2-3x+7)
=[ 2x^2-6x+3x-9](2x^2-3x+7)
=[2x(x-3) +3(x-3)](2x^2-3x+7)
= (2x+3) (x-3) (2x^2-3x+7)
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