Math, asked by js1322106, 10 months ago

find fast please please please​

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Answered by Anonymous
1

Answer:

4+ 1/√3

Step-by-step explanation:

3 + 1/√3  + 1/(√3+3) +1/(√3-3)

=3 + √3/√3*√3 +  (√3-3) / (√3+3)(√3-3) +  (√3+3)/(√3-3)(√3+3)

=3+√3/3 + (√3-3) /(3-9) + (√3+3)/(9-3)

=3+√3/3 + (√3-3) /(-6) + (√3+3)/6

=1/6 ( 18+2√3-√3+3+√3+3)

=1/6 (24+2√3)

=24/6 + 2√3/6

=4+ 1/√3

Answered by Ash34567
2

Answer:

4+ 1/√3

Step-by-step explanation:

3 + 1/√3  + 1/(√3+3) +1/(√3-3)

=3 + √3/√3*√3 +  (√3-3) / (√3+3)(√3-3) +  (√3+3)/(√3-3)(√3+3)

=3+√3/3 + (√3-3) /(3-9) + (√3+3)/(9-3)

=3+√3/3 + (√3-3) /(-6) + (√3+3)/6

=1/6 ( 18+2√3-√3+3+√3+3)

=1/6 (24+2√3)

=24/6 + 2√3/6

=4+ 1/√3

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