Find fifth derivative of y = x3 log x
Answers
Answered by
0
y log = x^3
hope this will help u
Answered by
2
Answer:
-6/x²
Step-by-step explanation:
y = x³*log x
diif.w.r.to.x,
dy/dx = 3x²log x + x³*1/x
= 3x²log x + x²
diff.w.r.to.x,
d²y/dx² = 6xlog x +3x²*1/x+2x
= 6xlog x + 5x
diff.w.r.to.x,
d³y/dx³ = 6log x + 6x*1/x + 5
= 6log x + 6 + 5
= 6log x + 11
diff.w.r.to.x,
d⁴y/dx⁴ = 0*log x + 6*1/x + 0
= 0 + 6/x + 0
= 6/x
= 6*x^(-1)
d⁵y/dx⁵ = 6*(-1*x^(-1-1))
= -6/x²
using formula
d/dx(x^n) = x^(n-1)
d/dx(log x) = 1/x
Similar questions