Math, asked by yagniksmita50, 2 months ago

find fifth term in (2x/3-3/2x)^6​

Answers

Answered by monikeshari1
0

Answer:

64x-729

Step-by-step explanation:

(2x/3-3/2x)^6

=(2x)^2-(3)^2/2x×3)^6

=(4x^2-9/2x×3)^6

=(2x-3)^6

=(2x×2x×2x×2x×2x×2x)-(3×3××3×3×3×3)

=64x-729

Similar questions