find fifth term in (2x/3-3/2x)^6
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Answer:
64x-729
Step-by-step explanation:
(2x/3-3/2x)^6
=(2x)^2-(3)^2/2x×3)^6
=(4x^2-9/2x×3)^6
=(2x-3)^6
=(2x×2x×2x×2x×2x×2x)-(3×3××3×3×3×3)
=64x-729
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