Find. Find amount and compound interest on rupes 10000 for 2 years at 10% per annum compounded annually.
Answers
Answered by
2
Answer:
Principal (P) = Rs.10000
Rate (R) = 10%
Time (n) = 2 years
Amount (A) = P (1 + R/100)ⁿ
=> A = 10000 (1 + 10/100)²
=> A = 10000 (11/10) (11/10)
=> A = Rs.12100
Compound Interest = A-P = Rs.(12100-10000) = Rs.2100
Answered by
0
Answer:
Simple interest= p*r*t/100
10000 × 10 × 3/100
➝ 300000/100
➝ 3000
Amount= p(1+r/100)t
10000 × (1+10/100)³
➝ 10000 × (110/100)³
➝ 10000×110/100×110/100×110/100
➝ 10000×1331000/1000000
➝ 10000×1.331
amount➝ 13310
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