Question

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Answer 1

Answer:

$To find :-</p><p></p><p>Distance travelled by train in \sf\blue{30\: sec}30sec \\ </p><p></p><p>Solution :-</p><p></p><p>Using 2nd equation of motion,</p><p></p><p>\to\:\:\sf{s = ut+ \frac{1}{2}{at}^{2} }→s=ut+21at</p><p></p><p>\to\:\:\sf{s = 20 \times 30 + \frac{1}{2} \times 0.5 \times {(30)}^{2} }→s=20×30+21×0.5×(30) \\ </p><p></p><p>\to\:\:\sf{ s =600 + \frac{1}{2} \times 0.5 \times 900 }→s=600+21×0.5×900</p><p></p><p>\to\:\:\sf{ s =600 + \frac{1}{2} \times450 }→s=600+21×450 \\ </p><p></p><p>\to\:\:\sf{s =600 + 225 }→s=600+225 \\ </p><p></p><p>\to\:\:\sf{ s = 825m}→s=825m \\ </p><p></p><p>\therefore\:\sf Distance travelled by train in 30sec is \\ {\bf{\pink{825m}} }∴Distancetravelledbytrainin30secis825m \\ </p><p></p><p>Additional Information :-</p><p></p><p>Few more equations of motion \\ </p><p></p><p>\sf\red{v = u + at}v=u+at \\ </p><p></p><p>\sf{ s = \dfrac{1}{2} (u + v) t }s=21(u+v)t \\ </p><p></p><p>\sf{v^2 = u^2 + 2as}v2=u2+2as \\ \\ </p><p></p><p>$