Question

find find find find find
the hcf of 144 and 60 by prime factrisation method
. . . .. . class 10

Answer 1

Answer:

12

Step-by-step explanation:

factors of 144=2*2*2*2*3*3

factors of 60=2*2*3*5

H. C. F=2^2*3

=12

Answer 2

Answer:

144= 2x2x2x2x3x3

60= 2x2x3x5

Common factor = 2,3,

HCF = 2x2x3

       = 12

hope this helps