Math, asked by Gajrajyadav, 1 year ago

find find the LCM and HCF of 43263 and 15295 by applying the fundamental theorem of arithmetic method

Answers

Answered by Rizal1
11
Step 1. Divide the larger number by the smaller one:
43,263 ÷ 15,295 = 2 + 12,673;
Step 2. Divide the smaller number by the above operation's remainder:
15,295 ÷ 12,673 = 1 + 2,622;
Step 3. Divide the remainder from the step 1 by the remainder from the step 2:
12,673 ÷ 2,622 = 4 + 2,185;
Step 4. Divide the remainder from the step 2 by the remainder from the step 3:
2,622 ÷ 2,185 = 1 + 437;
Step 5. Divide the remainder from the step 3 by the remainder from the step 4:
2,185 ÷ 437 = 5 + 0;
At this step, the remainder is zero, so we stop:
437 is the number we were looking for, the last remainder that is not zero.
This is the greatest common factor (divisor).
Least common multiple, lcm:
lcm (a; b) = (a × b) / gcf, gcd (a; b);
lcm (43,263; 15,295) = (43,263 × 15,295) / gcf, gcd (43,263; 15,295) = 661,707,585 / 437 = 1,514,205;
Least common multiple
lcm (43,263; 15,295) = 1,514,205 = 32 × 5 × 7 × 11 × 19 × 23;
Answered by Anujchauhan7861
7
Here, 43263>15295.So,
43263=15295*2+11673
15295=11673*1+3622
11673=3622*3+807
3622=807*4+394
807=394*2+19
394=19*26+10
19=10*1+9
10=9*1+1
9=1*9+0
so, H. C. F. (43263,15295)=1
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