Math, asked by yadayadv7u, 8 months ago

Find find the least number of 6 digit which is a perfect square With explation Koi ye mat khna mujhe nhi aata

Answers

Answered by mayajakhar79

Answer:

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100,489

The smallest 6-digit number that is a perfect square is 100,489 (317 x 317).

Answered by vanshikavikal448

hey mate your answer is here ⬇️⬇️⬇️

What is the smallest number of six digits that is a perfect square?

The smallest number of 6 digits=100000=10^5

Now the square root of 10^5:

√10^5=100√10=316.23 (As √10=3.1623)**

Now, to be the smallest number of six digits, the number must be greater than (316.23^2) and it's square root must be an integer.

Now the nearest integer to 316.23 that is greater than itself is 317.

So, the smallest 6 digits perfect square will be:

317^2=100489

**We can find out √10 easily by using this trick:

Nearest perfect squares to 10 are 9 and 16.

9=3^2 and 16=4^2.

so,√10 lies between 3 and 4.

2. Divide 10 by 3. 10/3 = 3.33 (you can round off your answer)

3. Average 3.33 and 3. (3.33 + 3)/2 = 3.1667

Repeat step 2: 10/3.1667 = 3.1579

Repeat step 3: Average 3.1579 and 3.1667. (3.1579 + 3.1667)/2 = 3.1623

Try the answer --> Is 3.1623 squared equal to 10? 3.1623 x 3.1623 = 10.0001

If this is accurate enough for you, you can stop! Otherwise, you can repeat steps 2 and 3.

Thanks for reading my answer. Hope this helps. If so, please consider upvoting.

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