Math, asked by zaidmohammed71pcqejs, 1 year ago

find find the polynomial whose zeros are root 3 by 2 and minus root 3 by 2

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Answered by albadichora
3
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Answered by mihirsthacker
12

α=√3\2

β=-√3\2

Sum of zeroes= -b\a=α+β=√3\2+(-√3\2)=0

Product of zeroes=c\a=αβ=√3\2×-√3\2=-3\4

P(x)=x² + (Sum of zeroes) x + (Product of zeroes)

x²+(0)x+-3\4

x²-3\4

    [OR]

4x²-3

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