find find the value of k if X + 1 is a factor of P[X] = x square + X + k
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1
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Answered by
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Answer:
If g(x)=x+1 is a factor of p(x)
then remainder will be 0.
Therefore p(x)=x+1
=x+1=0
=x=(-1)
P(x)=x^2+x+k
P(-1)=(-1)^2+(-1)+k=0
=(-1)+(-1)+k=0
K=2
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