find find the value of log 10 to the base 40 log 5 to the base 10 equals to a and log to the base 10 equals to b
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given
log 5 to base 10 = a ,
so 10 ^ a = 5
log 3 to base 10 = b
so 10 ^ b = 3
therefore
log 15 to base 40 = log (3 ×5 ) to base 40
= log (10 ^ b)( 10 ^ a) to base 40
= log 10^ (a+b)to base 40
= (a+b ) log 10 to base 40
= (a+b ) log (2 ×5 )to base 40
= (a+b ) log (2 × 10^a ) to base 40
= (a+b ) { log (2 ) to base 40 + log (10^a ) to base 40 }
= (a+b ) { log (2 ) to base 40 + a log (10 ) to base 40 }
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