Question

Find find the zero of the polynomial of a r (x) =(x _ 2)power 2 +( X + 2)

^ 2

Answer 1

x-2= 0......x=2now put value2+(2+2)=2+2=4...........I hope it will help you please do not report

Answer 2

${\pink{\bf{\huge{\star{Smile{\star}}}}}}$

${(x - 2)}^{2} + {(x + 2)}^{2} \\ {x}^{2} - 4x + 4 + {x}^{2} + 4x + 4 \\ 2 {x}^{2} + 8 = 0 \\ 2( {x}^{2} + 4) = 0 \\ {x}^{2} + 4 = 0 \\ {x}^{2} = - 4 \\ x = \sqrt{ - 4}$