Question

find find three consecutive even number whose sum is 96 ​

Answer 1

We know, every even number is of the form 2n.

So, let the first number be 2n.

Therefore, the second number will be 2n + 2.

Similarly, the third number will be 2n + 4.

Adding all these up and equating them to 96, we get:

2n + 2n + 2 + 2n + 4 = 96

6n + 6 = 96

6n = 90

n = 90/6 = 15

Therefore, the first number = 2n = 2(15) = 30

Second number = 2n + 2 = 2(15) + 2 = 32

Third number = 2n + 4 = 2(15) + 4 = 34

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