find find X and y in each of the following where de parallel to BC
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since DE||BC
angle DAB =angle ABC [ alternate interior angles]
therefore y=55°
since AC=BC
angle CBA= angle CAB [angles opposite to equal
sides of a triangle are
equal]
so, angle CAB =y
so in ∆ACB
x+y+y=180°
x+55°+55°=180°
x=70°
therefore [x=70°] [y=55°]
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