find first 3 terms of the arithmetic sequence with 5th term 26 and 7th term 68
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Let a be the first term of the AP and d be the common difference
a+3d = 26;
a + 9d = 68
6d = 42 ; d = 7
Putting d = 7 ; a= 5
The AP is 5,12,19,26,33,40,47,54,61,68
The sum of first 10 terms can be found by ( n/2)(2a+(n-1)d) = 5(10 + (9)(7)) = 365
Step-by-step explanation:
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