Question

find first five team of the sequence tn =4n-3.​

Answer 1

Answer:

Tn=4n-3

T1=4 ×1 -3 =1

T2=4×2-3=5

T3 =4×3-3 =9

T4=4×4-3= 13

T5=4×5-3=17

The first terms are

1 5 9 13 17 are in AP

Common difference is 4

Answer 2

Given: The equation is$t_{n} =4n-3$.

We have to find the first five-term of the above sequence.

• For this, we will put the values of n that are$(1,2,3,4,5)$ in the equation.
• And then we will solve the equation.

We are solving in the following way:

We have,

The equation is$t_{n} =4n-3$

For,

$n=1=> t_{n} =4n-3.=>t_{1}=4\times 1-3=>4-3=1\\n=2=>t_{2}=4\times 2-3=>8-3=5\\n=3=>t_{3}=4\times 3-3=>12-3=9\\n=4=>t_{4}=4\times 4-3=>16-3=13\\n=5=>t_{5}=4\times 5-3=>20-3=17$

Hence, the first five terms will be$1,5,9,13,17$.