Math, asked by chichan, 1 year ago

find first five terms of A.P wit series 3,7,11,15....
plzz solve this question fast i will mark you as brainlist

Answers

Answered by SurbhiAmbashta
1
Hey ,here is your answer !!
d= 4 so, answer is 3,7,11,15,19,23,27,31,35.............
Hope it helps you!!!
Attachments:

chichan: spevially bas pehle 5 series batana hai
SurbhiAmbashta: by adding 4 in previous terms..
chichan: ya
SurbhiAmbashta: ok bye
chichan: why you dont know how to solve
SurbhiAmbashta: mark my answer as brainliest if you wish ...thanks
chichan: nope
SurbhiAmbashta: ok ...no problem..☺☺☺☺
chichan: nope
SurbhiAmbashta: i am going to study now..bye
Answered by TRISHNADEVI
5
HERE IS YOUR ANSWER..⬇⬇

\underline{SOLUTION}

Given,

The A.P is 3 , 7 , 11 , 15.....

To find :- 5th term , t5.

Here ,

t1 = 3 , t2 = 7 , t3 = 11 , t4 = 15

t2 - t1 = 7 - 3 = 4

t3 - t2 = 11 - 7 = 4

t4 - t3 = 15 - 11 = 4

So,

a = 3

d = 4

•°• 5th term = t5

= a + ( 5 - 1) d

= 3 + 4 × 4

= 3 + 16

= 19

\underline{ANSWER}

5th term , t5 of the given A.P = 19

✝✝\underline{...THANK \: \: YOU...}✝✝

chichan: no solve full steps
TRISHNADEVI: it is solved by full step..
chichan: the given serues is 3,7,11,15.... solution: t2- t1 = 7 -3 =4 t3 - t2 = 11 - 7 =4 t4 - t3 = 15 - 11 = 4 this i an A.P the common difference is d =4
chichan: after this you you solve and give
TRISHNADEVI: ok..But it is given that the series is in A.P..So i think there is no need to prove the common difference..Like the way u r saying
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