Question

find first four terms of an AP whose first term is 3 and common difference is 4​

Answer 1

Answer:

The first four terms of AP are 3, 7, 11, 15.

Step-by-step explanation:

Given,

First term, a = 3

Common Difference, d = 4

Therefore, the first four terms of AP are a, a+d, a+2d, a+3d.

==> 3, 3+4, 3+(2*4), 3+(3*4)

==> 3, 7, 3+8, 3+12

==> 3, 7, 11, 15

Please mark me as Brilliant ☺️

Answer 2

Answer:

3,7,11,15

Step-by-step explanation:

a=3

d=4

a =3

a+d =7

a+2d = 11

a + 3d = 15