Question

Find first four terms of an AP whose first term is -3 and the common difference is -3

Answer 1

$\huge\bold{Answer:-}$

$\bold{<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u>:-}$

• The first term of an AP is -3
• The common difference of an AP is -3

$\bold{<u>T</u><u>o</u><u> </u>Find:-}$

• The First Four Term of the AP

$\bold{<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-}$

let , a be the first term of the ap

and , d be the common difference .

so , we know

The standard form of an AP is = a , ( a + d ) , ( a + 2d) , ( a + 3d ) .......

so , it is given that the first term is -3 and common difference is -3

Now ,

putting the values in the standard form of an Ap we get,

⟼ a , ( a + d ) , ( a + 2d) , ( a + 3d ) .......

⟼ -3 , [ - 3 + (-3)] , [ -3 + 2 × ( -3) ] , [ -3 + 3 × ( -3)].........

⟼ -3 , [ -3 - 3 ] , [ -3 - 6 ] , [ -3 - 9] ...............

⟼ -3 , -6 , - 9 , - 12 ...............

Therefore, the first four terms of the AP is -3 , -6 , -9 , -12 .

Know More :-

Formullas to find the number of terms in an Ap are -

• Tn = a + ( n - 1) d

where,

a = First term of the ap

n = number of term of the ap

d = common difference of the ap

• Tn = l - ( n - 1 ) d

where,

l = last term of the ap

n = number of terms of the ap

d = common difference

Note :

The first formulla is to find the no. of term of the ap from the first .

And , the second one is to find the ap from the last term .