Question

find first four terms of ap whos first sum is a=10and common difference is d=5​

Answer 1

Step-by-step explanation:

Given, a=10 and d=3

First term, a

1

=a=10

Second term, a

2

=a+d=10+3=13

Third term, a

3

=a+2d=10+2×3=10+6=16

Fourth term, a

4

=a+3d=10+3×3=10+9=19.

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