Find first term of the sequence tn=2n+18
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Question
✳️Find first term of the sequence tn=2n+18
Solution ⬇️
✍️tn=2n+18
✍️a+(n-1)d=2n-5+24
✍️a+(n-1)d=24+5(n-1)
✳️ Comparing on both the sides
✍️a=24 : d=5
✍️T1(a)=24
✍️by using Formula
✍️t2=t1+d
✍️t2=24+5=29
✍️t3=t2+d
✍️t3=29+5=34
✳️ therefore the 1st three terms are 24, 29 and 34
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