Question

find first the sum of first ten multiples of 2​

Answer 1

Answer:

Here, a = 2 , n = 10 , d = 2

Sn =

$\frac{n}{2} {2a + (n - 1)d}$

$= \frac{10}{2} \times (2 \times 2 + (10 - 1) \times 2)$

$= (5 \times 4) +( 9 \times 2)$

$= 20 + 18$

$= 38$