find first three natural numbers such that the sum of the first two numbers is 15 more than third
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Let the numbers be n, n+1 , n+2. (since its mentioned first three which means consecutive)
Given,
n + n+1 = 15 + n+2
2n + 1 = 17 + n
n = 16
Hence the numbers are 16, 17, 18
Given,
n + n+1 = 15 + n+2
2n + 1 = 17 + n
n = 16
Hence the numbers are 16, 17, 18
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Answer
Let numbers = x, x+1, x+2
x + x + 1 = x + 2 + 15
=> 2x = 17 + x - 1
=> x = 16
Numbers = 16, 17, 18
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