Question

Find first two moment in binomial and normal distribution

Answer 1

This bionomail 1 moments = 0 2 moments = npq ie 3 3 moment = npq(q-p) = 3 X 0.5 = 3/2 4 moment = 3 ( npq)^2 + npq (1-6pq ) = 3(3) ^ 2 + 3 ( 1- 6 ( 0.1875) = = 26.625