Question

Find five consecutive terms in an A.P., such
that the sum of the first three consecutive
terms is 6 and the sum of
the remaining
two terms is 14​

Answer 1

Answer:

0,2,4,6,8

Step-by-step explanation:

let the AP consecutive terms x1, x1+d, x1+2d, x1+3d, x1+4d

(x1)+(x1+d)+(x1+2d )=6

3x1 +3d = 6

x1 + d = 2.......(1)

(x1+3d)+(x1+4d) =14

2x1 + 7d =14....(2)

(1) + (2)

then we get d= 2

put the value of d in (1)

therefore x1 =0

then put the values of d and x1 in consecutive terms