Question

Find five consecutive terms in an A.P such that their sum is 60 and the product
of the third and the fourth term exceeds the fifth by 172.​

Answer 1

Step-by-step explanation:

let the terms are

a-2d, a-d ,a,a+d,a+2d

according to the question

a-2d+ a-d + a + a+d+ a+2d = 60

5a = 60

a = 12

now

a( a+d) = a+2d + 172

12( 12+d) = 12 + 2d + 172

144 + 12d = 184 + 2d

10 d = 184-144 = 40

d = 4

so the ap is

4,8,12,16 ,20

Answer 2

Find five consecutive terms in an A.P such that their sum is 60 and the product

of the third and the fourth term exceeds the fifth by 172.​