Question

find five number in G.P, such that there product is 1024 and 5^th term is square of third term given that term are positive .

Answer 1

Step-by-step explanation:

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Answer 2

⊰G⊱⊰i⊱⊰v⊱⊰e⊱⊰n⊱ :-

$( t_{5}) = ( a {r}^{2} )^{2}$

⊰s⊱⊰o⊱⊰l⊱⊰u⊱⊰t⊱⊰i⊱⊰o⊱⊰n⊱⊰s⊱

let a, ar, ar^2 , ar^3 ar^4 -----five term

therefore

ar^4 = (ar^2)^2

a =1

the product of five no. are

1×r×r^2×r^3r^4 = r^10 = 1024

r = +- 2

thus .

gp is 1,2,4,8,16