Math, asked by chandini88, 1 year ago

find five numbers in AP whose sum is 25/2 and the ratio of the first to the last terms is 2/3​

Answers

Answered by shekarmercy2577
0

Answer:

Step-by-step explanation:

Two dices are thrown at same time and the product of number appearing on them is noted find the probability that the product is a prime number

Answered by Anonymous
12

Answer:

Given

Sum of 5 terms of AP = 25/2

Ratio of 1st and last term = 2: 3

Let the first and last term of AP as 2x and 3x respectively.

So , according to the formula

Sn = n/2( 1st term+ last term)

25/2 = 5(2x+3x)/2

25/2 = 5(5x)/2

25/2 = 25x/2

25 = 25x

x = 1

So the value of X is 1

1st term = 2x = 2× 1 = 1

Last term= 3x = 3×1. = 3

So 1st and last term are 2 and 3 respectively

Now

an = a+ (n-1) d

3 = 2 + 4d

1 = 4d

d = 1/4

AP sequence will

2¼ , 2½, 2¾, 3

Hope it helps

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