Question

Find five numbers in ap whose sum is 25 and the sum of whose square is 135​

Answer 1

(x - 2d) + (x - d) + x + (x + d) + (x + 2d) = 25

x = 5

(5 - 2d)^2 + (5 - d)^2 + 5^2 + (5 + d)^2 + (5 + 2d)^2 = 135

25 - 20d + 4d^2 + 25 - 10d + d^2 + 25 + 25 + 10d + d^2 + 25 + 20d + 4d^2 = 135

10d^2= 10

d = 1

thus the five numbers are:

3, 4, 5, 6, 7

Check:

3 + 4 + 5 + 6 + 7 = 25

9 + 16 + 25 + 36 + 49 = 135

Answer 2

i hope this helps you solve the problem plz mark as brainliest