Find five rational numbers between 1 and 2.
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Answered by
18
Heya ☺
Let x = 1 and y = 2
y > x ; n = 5
d = y-x/n+1
= 2-1/5+1
= 1/6
1st rational number = x + 1/6
= 1 + 1/6
= 6+1/6
= 7/6
2nd rational number = x + 2d
= 1 + 2 × 1/6
= 1 + 1/3
= 3+1/3
= 4/3
3rd rational number = x + 3d
= 1 + 3 × 1/6
= 1 + 1/2
= 2+1/2
= 3/2
4th rational number = x + 4d
= 1 + 4 × 1/6
= 1 + 2/3
= 3+2/3
= 5/3
5th rational number = x + 5d
= 1 + 5 × 1/6
= 1 + 5/6
= 6+5/6
= 11/6
Five rational numbers between 1 and 2 are 7/6 ; 4/3 ; 3/2 ; 5/3 ; 11/6.
Thanks
Let x = 1 and y = 2
y > x ; n = 5
d = y-x/n+1
= 2-1/5+1
= 1/6
1st rational number = x + 1/6
= 1 + 1/6
= 6+1/6
= 7/6
2nd rational number = x + 2d
= 1 + 2 × 1/6
= 1 + 1/3
= 3+1/3
= 4/3
3rd rational number = x + 3d
= 1 + 3 × 1/6
= 1 + 1/2
= 2+1/2
= 3/2
4th rational number = x + 4d
= 1 + 4 × 1/6
= 1 + 2/3
= 3+2/3
= 5/3
5th rational number = x + 5d
= 1 + 5 × 1/6
= 1 + 5/6
= 6+5/6
= 11/6
Five rational numbers between 1 and 2 are 7/6 ; 4/3 ; 3/2 ; 5/3 ; 11/6.
Thanks
Answered by
6
first = (1+2)/2 =3/2
second =(3/2 +2 )/2 = [(3+4)/2]/2 =[7/2]/2 = 7/4
third = (3/2 +1)/2 = [(3+2)/2]/2 = (5/2)/2 = 5/4
fourth = (3/2+7/4)/2 = [(6+7)/4]/2 = (13/4)/2 = 13/8
fifth = (13/8+5/4)/2 =[(13+10)/8]/2 =(23/8)/2 = 23/16
i hope this will help you
- by ABHAY
second =(3/2 +2 )/2 = [(3+4)/2]/2 =[7/2]/2 = 7/4
third = (3/2 +1)/2 = [(3+2)/2]/2 = (5/2)/2 = 5/4
fourth = (3/2+7/4)/2 = [(6+7)/4]/2 = (13/4)/2 = 13/8
fifth = (13/8+5/4)/2 =[(13+10)/8]/2 =(23/8)/2 = 23/16
i hope this will help you
- by ABHAY
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