Question

Find five rational numbers between 3/7 and 4/7

Answer 1

5 rational numbers between 3/7 and 4/7 so multiply 6 on both fraction
3/7 × 6/6 = 18/42
4/7×6/6 = 24/42
then
5 rational numbers between them are
19/42, 20/42, 21/42, 22/42, 23/42

Answer 2

Answer:

Required 5 Rational numbers are

3/7 =18/42<($\frac{19}{42},\frac{20}{42},\frac{21}{42},\frac{22}{42},\frac{23}{42}$)<24/42 = 4/7

Explanation:

Given two Rational numbers 3/7 and 4/7

Since , we want 5 rational numbers,

We must multiply numerator and denominator by (5+1)=6

i.e $\frac{3}{7} = \frac{3\times6}{7\times6}= \frac{18}{42}$

and

$\frac{4}{7}=\frac{4\times6}{7\times 6}=\frac{24}{42}$

Now,

3/7 =18/42 <19/42<20/42<21/42<23/42<24/42 = 4/7

Therefore,

Required 5 Rational numbers are

3/7 =18/42<($\frac{19}{42},\frac{20}{42},\frac{21}{42},\frac{22}{42},\frac{23}{42}$)<24/42 = 4/7

Note: There exist infinite number of rational numbers between any two given Rational numbers.

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