find focal distance of the point (4,4) on parabola y²=4x
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y
2
=4x
focal distance = 10 units
comparing with y
2
=4ax
4a=4
a=1
concept : coordinates of parabola which is open rightward y
2
=4ax(a,0)
Focal distance = 2a
∴ coordinators of focus (1,0)
Focal distance =10
∴ x+1=10
x=9
y
2
=4×9 ∴ coordinators are =(9,6)
y=±6 =(9,-6)
Step-by-step explanation:
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