Question

find for x for the above equation​

Answer 1

Answer:

$\sqrt{ \frac{p}{q} } = ( { \frac{q}{p} })^{1 - 2x} \\ \\ ({ \frac{p}{q} })^{ \frac{1}{2} } = ( { \frac{q}{p} })^{1 - 2x} \\ \\ ( { \frac{q}{p} })^{ - \frac{1}{2} } = ( { \frac{q}{p} })^{1 - 2x} \\ \\ \sf \underline {comparing \: both \: sides} \rightarrow \\ \\ - \frac{1}{2} = 1 - 2x \\ \\ 2x = 1 - \frac{1}{2} \\ \\ 2x = \frac{1}{2} \\ \\ \implies \boxed{x = \frac{1}{4}}$

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