Find force F in the diagram below given that the liquid is mercury of density 13600kg/m3 (5mks
Answers
Answered by
1
Answer:
Pressure, p =
force
area
= 2
280 N 28000 Pa
0.010 m = 28 kPa
That is, the pressure produced by the piston is 28 kPa
it is exameple
Answered by
1
Answer:
Density of mercury = 13600 kg per m cube
Relative density = density of mercury ÷ density of water
Relative density = 13600 ÷1000
Therefore relative density = 13.6
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