Question

find force of attraction between two point charge of magnitude 1microcolumb each placed at a distance of 1 m.also,state the nature of charges.

Answer 1

Use the formula , F= (q1.q2 / 4* pi* epsilon * r^2 )

= (1 * 1C )/(4*pi*8.854.10^-12 * 1)

=9 x 10^9 N

NATURE OF CHARGES:

→When two charges have the same sign

their product is positive,

which means the force vector is directed with the separation vector (r̂)

and the action is repulsive.

→When two charges have the opposite sign

their product is negative,

which means the force vector is directed against the separation vector (r̂)

and the action is attractive.