find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742
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Let the four consecutive even integers be x, x+2, x+4 and x+6.
According to the question, x+x+2+2(x+4+x+6)=742
=>2x+2+2(2x+10) = 742
=>2(x+1+2x+10) = 2 × 371
=>3x+11= 371
=>3x= 371-11 = 360
=>x=360/3=120
Thus, the required numbers are :
x=120
x+2=120+2=122
x+4=120+4=124
x+6=120+6=126
Pls mark my ans as the brainliest
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