Question

find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742​

Answer 1

Step-by-step explanation:

let ,

four consecutive even number be

x ,x+2,x+4,x+6

then

x+x+2+2(x+4+x+6)=742

2x+2+2(2x +10)=742

2x+2+4x+20=742

6x+22= 742

6x= 742-22

6x=720

x=720/6

x=120

hence four consecutive even number =

x=120

x+2=122

x+4=124

x+6=126