Question

find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 742​

Answer 1

Hey there:)

Step-by-step explanation:

Let the four consecutive even integers be: x, x+2, x+4, x+6

(x + x+2) + 2(x+4 + x+6) = 742

(2x+2) + 2(2x+10) = 742

2x+2 + 4x+20 = 742

6x + 22 = 742

6x = 742- 22

6x = 720

x = 120

the four consecutive even integers are :x=120

                                                                x+2=122

                                                                x+4=124

                                                               x+6=126

hope it helps!!!