Question

Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth.​

Answer 1

Answer:

The numbers are : 8 , 10 , 12 and 14

Step-by-step explanation:

let the four consecutive even integers are :

x , x+2 , x+4 , x+6

sum of first three = 2 + 2( the fourth )

x + x + 2 + x + 4 = 2 + 2( x +6 )

3x + 6 = 2 + 2x + 12

3x - 2x = 14 - 6

x = 8

so the numbers are :

8 , 10 , 12 and 14

Answer 2

Answer:

4;6;8;10

Step-by-step explanation:

let the numbers are X,X+2,X+4,X+6

X+X+2+X+4+2=2(X+6)

3x+8=2x+12

3x-2x=12-8

X=4

4,4+2=6,4+4=8,4+6=10