Question

Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth.

Answer 1

Answer:

4,6,8,10

Step-by-step explanation:

let the integers be x, x+2, x+4, x+6

A.T.Q.

x+x+2+x+4+2 = 2(x+6)

3x+8 = 2x+12

3x-2x = 12-8

x = 4

now putting x = 4 values of integers come out to be 4, 6, 8, 10