Question

Find four consecutive in terms A.P whose sum is 20 and the sum of whose squares is 120.​

Answer 1

Now, a = 5 ; d = 1 (ignoring the -'ve value)

The four consecutive terms are:

a-3d = 5-3 = 2

a-d = 5-1 = 4

a+d = 5+1 = 6

a+3d = 5+3 = 8

The terms are 2, 4, 6, 8

$\underline{\mathfrak{\huge{Thank\:You}}}$

Answer 2

Answer:

Step-by-step explanation: