Question

Find four consecutive integers whose sum is 114.

Answer 1

let first integer be a
second be a+1
third a+2
fourth a+3
according to question
sum of the four consecutive integer is =114
4a+1+2+3=114
4a+6=114
4a=114-6
4a=108
a=27
so the first integer=27
second integer =28
third int=29
fourth int=30

Answer 2

let the first integer be x
then the next 3 would be x+1 , x+2 &x+3


a q
x+x+1+x+2+x+3=114
4x+6=114
4x=114-6=108
x=108/4
=27

THUS THE INTEGERS ARE 27 ,28,29 &30